(x-2)^3+(3x-1)(3x+1)=(x+1)^3(-2)^3+(3x-1)(3x+1)=(x+1)^3

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Solution for (x-2)^3+(3x-1)(3x+1)=(x+1)^3(-2)^3+(3x-1)(3x+1)=(x+1)^3 equation: 



(x-2)^3+(3x-1)(3x+1)=(x+1)^3(-2)^3+(3x-1)(3x+1)=(x+1)^3

We move all terms to the left:

(x-2)^3+(3x-1)(3x+1)-((x+1)^3(-2)^3+(3x-1)(3x+1))=0

We use the square of the difference formula

9x^2+9x^2+(x-2)^3-1+1=0

We add all the numbers together, and all the variables

18x^2+(x-2)^3=0

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